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Question
P is the centre of the circle and its radius is
10 cm. Distance of a chord AB from the centre is 6 cm. Find the length of chord AB.
Solution
seg PM ⊥ chord AB
In right angled triangle Δ APM
AM2 + PM2 = AP2 ........ (by Pythagoras theorem)
∴ AM2 + 62 = 102
∴ AM2 = 100 - 36
∴ AM2 = 64
∴ AM = 8 cm 
We know perpendicular from centre bisects the chord so AM = MB
∴ AB = 2 × AM
∴ AB = 2 × 8
∴ AB = 16 cm
∴ lenght of chord AB = 16 cm.
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