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Question
Plane wavefront of Light of wavelength 6000 Å is incident on two slits on a screen perpendicular to the direction of light rays. If the total separation of 10 brights fringes on a screen 2m away is 2 cm, find the distance between the slits.
Solution
Given,
Distance between 10 fringes = 2 cm = 0.02 m
λ = 6000 Å
= 6000 × 10-10 m
∴ Fringe width, w = `0.02/10` = 0.002 m
D = 2 m
Fringe width w = `(lambda "D")/"d"`
d = `(lambda "D")/"w"`
`= (6,000 xx 10^-10 xx 2)/0.002`
= 6 × 10-4 m
The distance between the slits is 6 × 10-4 m.
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