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Question
Prove that (4, 3), (6, 4) (5, 6) and (3, 5) are the angular points of a square.
Solution
Let A (4, 3); B (6, 4); C (5, 6) and D (3, 5) be the vertices of a quadrilateral. We have to prove that the quadrilateral ABCD is a square.
So we should find the lengths of sides of quadrilateral ABCD.
`AB = sqrt((6 - 4)^2 + (4 -3)^2)`
`= sqrt(4 + 1)`
`= sqrt5`
`BC = sqrt((6 - 5)^2 + (4 - 6)^2)`
`= sqrt(1 + 4)`
`= sqrt5`
`CD = sqrt((3 - 5)^2 + (5 - 6)^2)`
`= sqrt(4 + 1)`
`= sqrt5`
`AD = sqrt((3 - 4)^2 + (5 - 3)^2)`
`= sqrt(1+ 4)`
`= sqrt5`
All the sides of quadrilateral are equal.
So now we will check the lengths of the diagonals.
`AC = sqrt((5 - 4)^2 + (6 - 3)^2)`
`=sqrt(1 + 9)`
`= sqrt(10)`
`BC = sqrt((6 - 3)^2 + (4 - 5)^2)`
`= sqrt(9 + 1)`
`= sqrt10`
All the sides as well as the diagonals are equal. Hence ABCD is a square.
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