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Find the value of k, if the points A (8, 1) B(3, −4) and C(2, k) are collinear. - Mathematics

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Question

Find the value of k, if the points A (8, 1) B(3, −4) and C(2, k) are collinear.

 
Answer in Brief

Solution

The formula for the area ‘A’ encompassed by three points( x1 , y1) , (x2 , y2)  and (x3 , y3)  is given by the formula,

\[∆ = \frac{1}{2}\left| \left( x_1 y_2 + x_2 y_3 + x_3 y_1 \right) - \left( x_2 y_1 + x_3 y_2 + x_1 y_3 \right) \right|\]

If three points are collinear the area encompassed by them is equal to 0.

The three given points are A(8,1), B(3,4) and C(2,k). It is also said that they are collinear and hence the area enclosed by them should be 0.

\[∆ = \frac{1}{2}\left| \left( 8 \times - 4 + 3 \times k + 2 \times 1 \right) - \left( 3 \times 1 + 2 \times - 4 + 8 \times k \right) \right|\]

\[ 0 = \frac{1}{2}\left| \left( - 32 + 3k + 2 \right) - \left( 3 - 8 + 8k \right) \right|\]

\[ 0 = \frac{1}{2}\left| - 25 - 5k \right|\]

\[k = - 5\]

Hence the value of ‘k’ for which the given points are collinear is k = - 5.

 

 

 

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Chapter 6: Co-Ordinate Geometry - Exercise 6.5 [Page 54]

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RD Sharma Mathematics [English] Class 10
Chapter 6 Co-Ordinate Geometry
Exercise 6.5 | Q 19 | Page 54

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