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Question
Prove that
Refractive index = `"Real depth"/"Apparent depth"`
Solution
In the given figure,
In rt. Δ DKA
Sin i = `("DK")/("AD")`
In rt. Δ DKB, Sin r = `("DK")/("BD")`
`""_mmu_a ∴ sin i/sin r = ("DK"/"AD")/("DK"/"BD")`
`sin i/sin r = "BD"/"AD"`
Or `""_amu_m = 1/(""_mmu_a)`
`""_amu_m = "AD"/"BD"`
Since point D is very close to K
`""_amu_m = "AK"/"K"`
`""_amu_m = "Real depth"/"Apparent depth"`
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