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Represent the following situation in the form of a quadratic equation: The area of a rectangular plot is 528 m2. The length of the plot (in metres) is one more than twice its breadth. - Mathematics

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Question

Represent the following situation in the form of a quadratic equation:

The area of a rectangular plot is 528 m2. The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot.

Sum

Solution

Let the breadth of the rectangular plot = x m

Hence, the length of the plot is (2x + 1) m.

Formula of area of rectangle = length × breadth = 528 m2

Putting the value of length and width, we get

(2x + 1) × x = 528

⇒ 2x2 + x = 528

⇒ 2x2 + x - 528 = 0

⇒ 2x2 + 33x - 32x - 528 = 0

⇒ x(2x + 33) - 16(2x + 33) = 0

⇒ (2x + 33)(x - 16) = 0

⇒ 2x + 33 = 0 and x - 16 = 0

⇒ 2x = -33 and x = 16

⇒ x = `(-33)/2` and x = 16

Since,

Width of rectangular plot = x m = 16 m

Length of rectangular plot = 2x + 1 m

= 2 × 16 + 1 m

= 32 + 1 m

= 33 m

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Chapter 4: Quadratic Equations - Exercise 4.1 [Page 73]

APPEARS IN

NCERT Mathematics [English] Class 10
Chapter 4 Quadratic Equations
Exercise 4.1 | Q 2.1 | Page 73
RD Sharma Mathematics [English] Class 10
Chapter 4 Quadratic Equations
Exercise 4.11 | Q 9 | Page 71

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