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Question
Show that `(4/3 m - 3/4 n)^2 + 2mn = 16/9 m^2 + 9/16 n^2`
Solution
L.H.S = `(4/3 m - 3/4n)^2 + 2mn`
= `(4/3 m)^2 - 2(4/3 m)(3/4 n) + (3/4 n)^2 + 2mn`
= `16/9 m^2 - 2mn + 9/16 n^2 + 2mn`
= `16/9 m^2 + 9/16 n^2` = R.H.S
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