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Maharashtra State BoardSSC (English Medium) 6th Standard

Shubham’s age today is 12 years and his father’s is 42 years. Shubham’s mother is younger than his father by 6 years. Find the ratio of Shubham’s age to his mother’s age when Shubham was 10 years old. - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Shubham’s age today is 12 years and his father’s is 42 years. Shubham’s mother is younger than his father by 6 years. Find the ratio of Shubham’s age to his mother’s age when Shubham was 10 years old.

Sum

Solution

Shubham’s age today = 12 years

Shubham’s father age today = 42 years

∴ Shubham’s mother age today = Shubham’s father age today − 6 years

= 42 years − 6 years

= 36 years

Difference between the present age of Shubham and when he was 10 years old

= 12 years − 10 years = 2 years

∴ Shubham's mother age when Shubham was 10 years old

= 36 years − 2 years = 34 years

Ratio of Shubham’s age to his mother’s age when Shubham was 10 years old 

= 10 years : 34 years

= `10/34`

= `(10 div 2)/(34 div 2)`     (HCF of 10 and 34 = 2)

= `5/17`

= 5 : 17

Thus, the ratio of Shubham’s age to his mother’s age when Shubham was 10 years old is `5/17` or 5 : 17.

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Chapter 11: Ratio and Proportion - Practice Set 28 [Page 59]

APPEARS IN

Balbharati Mathematics [English] 6 Standard Maharashtra State Board
Chapter 11 Ratio and Proportion
Practice Set 28 | Q 6.3 | Page 59
Balbharati Integrated 6 Standard Part 3 [English Medium] Maharashtra State Board
Chapter 3.2 Ratio-Proportion
Practice Set 28 | Q 6. (3) | Page 54
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