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Question
Simplify:
`("a" - 1/"a")^2 + ("a" + 1/"a")^2`
Sum
Solution
`("a" - 1/"a")^2 + ("a" + 1/"a")^2`
= `("a")^2 + (1/"a")^2 - 2("a") (1/"a") + ("a")^2 + (1/"a")^2 + 2("a")(1/"a")`
= `"a"^2 + (1)/"a"^2 - 2 + "a"^2 + (1)/"a"^2 + 2`
= `2"a"^2 + (2)/"a"^2`.
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