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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 8

Simplify (p – 2)(p + 1)(p – 4) - Mathematics

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Question

Simplify (p – 2)(p + 1)(p – 4)

Sum

Solution

(p – 2)(p + 1)(p – 4) = (p + (– 2))(p + 1)(p + (– 4))

Comparing (p – 2)(p + 1)(p – 4) with (x + a)(x + b)(x + c) we have x = p, a = – 2, b = 1, c = – 4.

(x + a)(x + b)(x + c) = x2 + (a + b + c)x2 + (ab + bc + ca)x + abc

= p3 + (– 2 + 1 + (– 4))p2 + (– 2)(1) + (1)(– 4) + (– 4)(– 2))p + (– 2)(1)(– 4)

= p3 + (– 5)p2 + (– 2 + (– 4) + 8)p + 8

= p2 – 5p2 + 2p + 8

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Expansion of (x + a)(x + b)(x + c)
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Chapter 3: Algebra - Exercise 3.3 [Page 91]

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Samacheer Kalvi Mathematics [English] Class 8 TN Board
Chapter 3 Algebra
Exercise 3.3 | Q 4 | Page 91
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