Advertisements
Advertisements
Question
Solve using formula.
5x2 + 13x + 8 = 0
Solution
5x2 + 13x + 8 = 0
On comparing with the equation ax2 + bx + c = 0
a = 5, b = 13 and c = 8
Now
b2 - 4ac = (13)2 - 4 × 5 × 8
= 169 - 160
= 9
\[x = \frac{- b \pm \sqrt{b^2 - 4ac}}{2a}\]
\[x = \frac{- 13 \pm \sqrt{9}}{2 \times 5}\]
\[x = \frac{- 13 \pm 3}{10}\]
To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.
\[ x = \frac{- 13 + 3}{10} \text{ or } x = \frac{- 13 - 3}{10}\]
\[ x = \frac{- 10}{10} \text{ or } x = \frac{- 16}{10}\]
Rearrange and isolate the variable to find each solution
\[ x = - 1 \text{ or }x = \frac{- 8}{5}\]
APPEARS IN
RELATED QUESTIONS
Compare the given quadratic equation to the general form and write values of a,b, c.
y2 = 7y
Solve using formula.
x2 + 6x + 5 = 0
Solve using formula.
x2 – 3x – 2 = 0
Solve using formula.
3m2 + 2m – 7 = 0
Solve using formula.
5m2 – 4m – 2 = 0
Solve using formula.
y2 + `1/3`y = 2.
Find the value of discriminant of the following equation.
2y2 − y + 2 = 0
Two roots of quadratic equation is given ; frame the equation.
\[1 - 3\sqrt{5} \text{ and } 1 + 3\sqrt{5}\]
Determine the nature of root of the quadratic equation.
\[3 x^2 - 5x + 7 = 0\]
Determine the nature of root of the quadratic equation.
\[\sqrt{3} x^2 + \sqrt{2}x - 2\sqrt{3} = 0\]
Determine the nature of root of the quadratic equation.
m2 - 2m + 1 = 0
The sum of two roots of a quadratic equation is 5 and sum of their cubes is 35, find the equation.
Find quadratic equation such that its roots are square of sum of the roots and square of difference of the roots of equation \[2 x^2 + 2\left( p + q \right)x + p^2 + q^2 = 0\]
The difference between squares of two numbers is 120. The square of smaller number is twice the greater number. Find the numbers.