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Question
Determine the nature of root of the quadratic equation.
m2 - 2m + 1 = 0
Solution
Given:
⇒ m2 - 2m + 1 = 0 compare with ax2 + bx + c = 0
We get,
⇒ a = 1, b = - 2, c = 1
The value of the discriminant is
∴ b2 - 4ac
= (-2)2 - 4(1) (1)
= 4 - 4
= 0
∴ b2 - 4ac = 0. Hence, roots are real and equal.
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