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Question
Some heat is given to 120 g of water and its temp. rises by 10 K. When the same amount of heat is given to 60 g of oil, its temp. rises by 40 K. The Sp. heat of water is 4200 J/kgK. Calculate:
(a) The amount of heat in joules given to water,
(b) The specific heat capacity of the oil.
Solution
For water
m = 120 g = 0.12 kg
ΔT = 10 K
C = 4200 J/ KgK
Q = m x c x ΔT
= 0.12 x 4200 x 10
= 5040 J
For oil:
Q = 5040 J
m = 60 g = 0.06 kg
ΔT = 40 K
C = `"Q"/("m" xx Δ"T")`
= `5040/(0.06 xx 40)` = 2100 J/kgK
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