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1 Kg of Molten Lead at Its Melting Point of 327°C is Dropped into 1 Kg of Water at 20°C. Assuming No Loss of Heat, Calculate the Final Temp. of Water. - Physics

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Question

1 kg of molten lead at its melting point of 327°C is dropped into 1 kg of water at 20°C. Assuming no loss of heat, calculate the final temp. of water. (Sp. heat of lead = 130 J/kg°C, latent heat of lead = 27000 J/kg and Sp. heat of water = 4200 J/kg°C).

Numerical

Solution

Let the final temperature of the mixture be t

Heat lost by lead = Heat gained by water

m1L + m1 x CL x (327 - t) = mz x cw x (t - 20)

1 x 27000 + 1 x 130 x (327 - t) = 1 x 4200 x (t - 20)

27000 + 42510 _ 130t = 4200t - 84000

t = 35.45°C

So, the final temperature of water is 35.45°C.

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Chapter 5: Heat - Exercise 3 [Page 247]

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Frank Physics - Part 2 [English] Class 10 ICSE
Chapter 5 Heat
Exercise 3 | Q 8 | Page 247

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