Advertisements
Advertisements
Question
Options
True
False
Solution
False.
Concept Insight: (i) There is inverse relation between atomic size and electron affinity. More is the size, less is the electron affinity and vice versa because more is the size of atom, more is the distance between the nucleus and last shell to which electron enters. This results in decrease in force of attraction between the nucleus and incoming electron and hence the electron affinity decreases. Fluorine has smaller size than chlorine so it must have less electron affinity than chlorine.
APPEARS IN
RELATED QUESTIONS
Arrange the following as per the instruction given in the brackets:
He, Ar, Ne (Increasing order of the number of electron shells)
Give reason:
Electron affinity of halogens is comparatively high ?
Which has higher E.A. fluorine or Neon?
A, B, C are three elements in which B is an inert gas other than helium.With this information complete the following table.
| Element | Atomic number | No. of electrons in the valence shell | Group to which the element belongs |
| A | Z - 1 | ||
| B | Z | ||
| C | Z + 1 |
Also, explain the following : Electron affinity of element A is more than that that of element C.
Fill in the blank
Noble gases have ______ electron affinity.
Down the group, electron affinity ______.
Among the Period 2 elements, the element which has high electron affinity is
Arrange the following as per instruction given in the bracket.
Cl, F, Br, I (increasing electron affinity)
Arrange the following as per instruction given in the bracket.
Cl, F, Br, I (increasing electron affinity)
In Period 3 of the Periodic Table, element B is placed to the left of element A. On the basis of this information, choose the correct word from the option to complete the following statement:
The element A would probably have ______ electron affinity than B.
