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Question
Subtract:
2ab + 5bc – 7ac from 5ab – 2bc – 2ac + 10abc
Solution
We have,
2ab + 5bc – 7ac and 5ab – 2bc – 2ac + 10abc
The required difference is given by (5ab – 2bc – 2ac + 10abc) – (2ab + 5bc – 7ac)
= 5ab – 2bc – 2ac + 10abc – 2ab – 5bc + 7ac
= (5ab – 2ab) + (–2bc – 5bc) + (–2ac + 7ac) + 10abc ...[Grouping like terms]
= 3ab – 7bc + 5ac + 10abc
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