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Taking the volume of hydrogen as calculated in Q.19, what change must be made in Kelvin (absolute) temperature to return the volume to 2500 cm3 (pressure remaining constant)? - Chemistry

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Question

Taking the volume of hydrogen as calculated in Q.19, what change must be made in Kelvin (absolute) temperature to return the volume to 2500 cm3 (pressure remaining constant)?

Numerical

Solution

V1 = 714.29 cm3
P1 = P2 = P
T1 = 273 K
V2 = 2500 cm3
T2= ?
By using Charles's Law,

`("P"_1 "V"_1)/"T"_1 = ("PV"_2)/"T"_2`

Since P is constant, it cancels out.

`"V"_1/"T"_1 = "V"_2/"T"_2`

T2 = `("V"_2 xx "T"_1)/"V"_1`

T2 = `(2500 xx 273)/714.29`

T2 = 3.5 × 273

T2 = 955.5 K

∴ T2 = 3.5 times

∴ The temperature must be increased 3.5 times.

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Fundamental Laws of Gases - Temperature - Volume Relationship or Charles's Law
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Chapter 7: Study of Gas Laws - Exercise 7 (B) [Page 127]

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Selina Concise Chemistry [English] Class 9 ICSE
Chapter 7 Study of Gas Laws
Exercise 7 (B) | Q 20 | Page 127
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