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प्रश्न
Taking the volume of hydrogen as calculated in Q.19, what change must be made in Kelvin (absolute) temperature to return the volume to 2500 cm3 (pressure remaining constant)?
उत्तर
V1 = 714.29 cm3
P1 = P2 = P
T1 = 273 K
V2 = 2500 cm3
T2= ?
By using Charles's Law,
`("P"_1 "V"_1)/"T"_1 = ("PV"_2)/"T"_2`
Since P is constant, it cancels out.
`"V"_1/"T"_1 = "V"_2/"T"_2`
T2 = `("V"_2 xx "T"_1)/"V"_1`
T2 = `(2500 xx 273)/714.29`
T2 = 3.5 × 273
T2 = 955.5 K
∴ T2 = 3.5 times
∴ The temperature must be increased 3.5 times.
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