Question

88 cm³ of nitrogen is at a pressure of 770 mm mercury. If the pressure is raised to 880 mmHg, find by how much the volume will diminish, the temperature remaining constant.

Answer 1

V = 88 cm³ 

P = 770 mm

P₁ = 880 mm 

V₁= ? 

T = T₁

Using gas equation,

${\displaystyle \frac{\text{PV}}{\text{T}}=\frac{{\text{P}}_1{\text{V}}_1}{{\text{T}}_1}}$

${\displaystyle \frac{770\times 88}{\text{T}}=\frac{880\times {\text{V}}_1}{\text{T}}}$

V₁ = 77 cm³

Volume diminishes = 88 - 77 = 11 cm³