Advertisements
Advertisements
Question
The addition of HBr to 1-butene gives a mixture of products A, B and C
(A) | ![]() |
(B) | ![]() |
(C) | CH3 – CH2 – CH2 – CH2 – Br |
The mixture consists of:
Options
A and B as major and C as minor products
B as major, A and C as minor products
B as minor, A and C as major products
A and B as minor and C as major products
Solution
A and B as major and C as minor products
Explanation:
The reaction follows Markovnikov’s rule leading to giving 2° carbocation as an intermediate.
APPEARS IN
RELATED QUESTIONS
An alkene ‘A’ on ozonolysis gives a mixture of ethanal and pentan-3-one. Write structure and IUPAC name of ‘A’.
Propanal and pentan-3-one are the ozonolysis products of an alkene? What is the structural formula of the alkene?
Write a chemical equation for combustion reaction of the following hydrocarbon:
Butane
Write a chemical equation for combustion reaction of the following hydrocarbon:
Pentene
Arrange the halogens F2, Cl2, Br2, I2, in order of their increasing reactivity with alkanes.
Arrange the following hydrogen halides in order of their decreasing reactivity with propene.
Which of the following alkenes on ozonolysis give a mixture of ketones only?
(i) | CH3 – CH = CH – CH3 |
(ii) | \[\begin{array}{cc} \ce{CH3 - C - CH = CH2}\\ |\phantom{.......}\\ \ce{CH3}\phantom{....} \end{array}\] |
(iii) | ![]() |
(iv) | \[\begin{array}{cc} \phantom{...................}\ce{CH3}\\ \phantom{..............}/\\ \ce{(CH3)2 C = C}\\ \phantom{..............}\backslash\\ \phantom{...................}\ce{CH3} \end{array}\] |
What would be the main product when propene reacts with HBr?
In the presence of peroxide, HCl and HI do not give anti-Markovnikov's addition of alkenes because ______.
An alkene ‘A’ contains three C-C, eight C-H σ bonds and one C-C π bond. ‘A’ on ozonolysis gives two moles of an aldehyde of molar mass 44 u. Write the IUPAC name of ‘A’.