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Question
The age of a man is three times the age of his son. After 10 years, the age of the man will be double that of his son. Find their present ages.
Solution
Let the age of the son be x years.
Then, the man's age = 3x years.
After 10 years, their ages becomes
(x + 10) and (3x + 10) respectively.
As per given conditions,
`((x + 10))/((3x + 10)) = (1)/(2)`
⇒ 2x + 20 = 3x + 10
⇒ x = 10 years
Thus, the present age of the son is 10 years.
Then, the main's age = 30years.
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