Advertisements
Advertisements
Question
The area of ∆ABC is 8 cm2 in which AB = AC = 4 cm and ∠A = 90º.
Options
True
False
Solution
This statement is True.
Explanation:
We have, ABC is a right angled triangle at A, where sides are given AB = AC = 4 cm
∴ Area of a triangle ABC = `1/2` (Base × Height)
= `1/2` × AC × AB
= `1/2` × 4 × 4
= 8 cm2
APPEARS IN
RELATED QUESTIONS
Find the values of k so that the area of the triangle with vertices (k + 1, 1), (4, -3) and (7, -k) is 6 sq. units.
Prove that the points (a, b + c), (b, c + a) and (c, a + b) are collinear
If the coordinates of the mid-points of the sides of a triangle are (1, 1), (2, —3) and (3, 4), find the vertices of the triangle.
Find the value of k so that the area of the triangle with vertices A (k+1, 1), B(4, -3) and C(7, -k) is 6 square units
Find the value(s) of k so that the quadratic equation x2 − 4kx + k = 0 has equal roots.
The table given below contains some measures of the right angled triangle. Find the unknown values.
Base | Height | Area |
20 cm | 40 cm | ? |
Show that the ∆ABC is an isosceles triangle if the determinant
Δ = `[(1, 1, 1),(1 + cos"A", 1 + cos"B", 1 + cos"C"),(cos^2"A" + cos"A", cos^2"B" + cos"B", cos^2"C" + cos"C")]` = 0
The points (1,1), (-2, 7) and (3, -3) are ______.
The area of a triangle with base 4 cm and height 6 cm is 24 cm2.
Find the cost of laying grass in a triangular field of sides 50 m, 65 m and 65 m at the rate of Rs 7 per m2.