English
Tamil Nadu Board of Secondary EducationHSC Commerce Class 11

The correlation coefficient from the following data N = 25, ∑X = 125, ∑Y = 100, ∑X2 = 650, ∑Y2 = 436, ∑XY = 520 - Business Mathematics and Statistics

Advertisements
Advertisements

Question

The correlation coefficient from the following data N = 25, ∑X = 125, ∑Y = 100, ∑X2 = 650, ∑Y2 = 436, ∑XY = 520

Options

  • 0.667

  • − 0.006

  • – 0.667

  • 0.70

MCQ

Solution

0.667

Explanation:

r = `("N"sum"XY" - sum"X"sum"Y")/(sqrt("N"sum"X"^2 - (sum"X")^2) sqrt("N"sum"Y"^2 - (sum"Y")^2))`

= `(25(520) - 125 xx 100)/(sqrt(25 xx 650 - (125)^2) sqrt(25 xx 436 - (100)^2))`

= `(13000 - 12500)/(sqrt(16250 - 15625) sqrt(10900 - 10000))`

= `500/(sqrt625 sqrt900)`

= `500/(25 xx 30)`

= `2/3`

= 0.6666

= 0.667

shaalaa.com
Correlation
  Is there an error in this question or solution?
Chapter 9: Correlation and Regression Analysis - Exercise 9.3 [Page 228]

APPEARS IN

Samacheer Kalvi Business Mathematics and Statistics [English] Class 11 TN Board
Chapter 9 Correlation and Regression Analysis
Exercise 9.3 | Q 6 | Page 228
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×