Advertisements
Advertisements
Question
The cost of 5 pens and 8 pencils together cost Rs. 120 while 8 pens and 5 pencils together cost Rs. 153. Find the cost of a 1 pen and that of a 1pencil.
Solution
Let the cost of 1 pen and 1 pencil are ₹x and ₹y respectively.
Then as per the question
5x + 8y = 120 …….(i)
8x + 5y = 153 …….(ii)
Adding (i) and (ii), we get
13x + 13y = 273
⇒ x + y = 21 …….(iii)
Subtracting (i) from (ii), we get
3x – 3y = 33
⇒ x – y = 11 ………(iv)
Now, adding (iii) and (iv), we get
2x = 32 ⇒ x = 16
Substituting x = 16 in (iii), we have
16 + y = 21 ⇒ y = 5
Hence, the cost of 1 pen and 1 pencil are respectively ₹16 and ₹5.
APPEARS IN
RELATED QUESTIONS
The cost of 2 kg of apples and 1 kg of grapes on a day was found to be Rs 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs 300. Represent the situation algebraically and geometrically.
Find the value of k for which each of the following system of equations has infinitely many solutions :
2x + 3y = 2
(k + 2)x + (2k + 1)y - 2(k - 1)
Solve for x and y:
x – y = 3, `x/3 + y/2` = 6
Show that the system equations
2x - 3y = 5,
6x - 9y = 15
has an infinite number of solutions
Find the value of k for which the system of linear equations has an infinite number of solutions:
5x + 2y = 2k,
2(k + 1)x + ky = (3k + 4).
The sum of the digits of a two-digit number is 12. The number obtained by interchanging its digits exceeds the given number by 18. Find the number.
The sum of the numerator and denominator of a fraction is 8. If 3 is added to both of the numerator and the denominator, the fraction becomes `3/4`. Find the fraction.
The sum of the numerator and denominator of a fraction is 4 more than twice the numerator. If the numerator and denominator are increased by 3. They are in the ratio of 2: 3. Determine the fraction.
The sum of two numbers is 1/6 and the sum of their reciprocals is `1/3`. Find the numbers.
Write the number of solutions of the following pair of linear equations:
x + 3y – 4 = 0, 2x + 6y – 7 = 0.