Question

The diagonals of the rhombus is 12 cm and 16 cm. Find its perimeter. (Hint: the diagonals of rhombus bisect each other at right angles)

Answer 1

Here AO = CO = 8 cm

BO = DO = 6 cm ...(∴the diagonals of rhombus bisect each other at right angles)

∴ In ∆AOB, AB² = AO² + OB²

= 8² + 6²

= 64 + 36

= 100 = 10²

∴ AB = 10

Since it is a rhombus, all the four sides are equal.

AB = BC = CD = DA

∴ Its Perimeter = 10 + 10 + 10 + 10 = 40 cm