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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 8

In the figure, if ∠FEG ≡ ∠1 then, prove that DG2 = DE.DF - Mathematics

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Question

In the figure, if ∠FEG ≡ ∠1 then, prove that DG2 = DE.DF

Chart

Solution

Proof:

S.No. Statements Reasons
1.

∠FEG ≡ ∠1

⇒ ∠DEG = 180° − ∠FE

Given

linear pair

2.

∠FDG + ∠DGF = 1

∠EDG + ∠DFG = 1

Exterior angle = Sum of interior opposite angles

∵ ∠FDG = ∠EDG

3.

∠DEG = 180° − ∠FEG

∠DEG = 180° − ∠1

By 1
4.

In ΔDFG

∠DEG = 180° − [∠FDG + ∠DFG]

Angle sum property
5. ∠DGF = 180° − ∠1 By 2
6.

∠DGF = ∠DEG

By 3
7.

∠EDG = ∠EDG

Common in ΔFDG and ΔEDG
8. ∴ ∠DGE = ∠DFG Remaining angle by sum property and by 6
9. ∴ ΔDGF ∼ ΔDEG

By 6, 7, 8

By AAA similarity

10. `"DG"/"DE" = "GF"/"EG" = "DF"/"DG"` Corresponding sides of similar traingle are proportional
11.

`"DG"/"DE" = "DF"/"DG"`

DG.DG = DF.DE

DG2 = DE.DF

From 9
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Chapter 5: Geometry - Exercise 5.3 [Page 180]

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Samacheer Kalvi Mathematics [English] Class 8 TN Board
Chapter 5 Geometry
Exercise 5.3 | Q 7 | Page 180
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