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Question
The elevator shown in the following figure is descending with an acceleration of 2 m/s2. The mass of the block A is 0.5 kg. What force is exerted by the block A on the block B?
Sum
Solution
When the elevator is descending, a pseudo-force acts on it in the upward direction, as shown in the figure.
From the free-body diagram of block A,
\[mg - N = ma\]
\[N = m\left( g - a \right)\]
\[ \Rightarrow N = 0 . 5\left( 10 - 2 \right) = 4 N\]
So, the force exerted by the block A on the block B is 4 N..
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