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Question
The equations of two lines of regression are 4x + 3y + 7 = 0 and 3x + 4y + 8 = 0. Find the mean value of x and y.
Solution
The two regression lines are:
4x + 3y + 7 = 0 ...(i)
3x + 4y + 8 = 0 ...(ii)
We solve these equations simultaneously because the point `(barx, bary)` is on both regression lines.
Multiplying equation (i) by 4 and equation (ii) by 3 and subtracting both equations, we get
16x + 12y + 28 = 0
9x + 12y + 24 = 0
– – –
7x + 4 = 0
`x = -4/7`
Putting the value of x into equation (i), we get
`4 xx (-4/7) + 3y + 7 = 0`
`\implies -16/7 + 7 + 3y = 0`
`\implies 3y = 16/7 - 7`
= `(16 - 49)/7`
= `-33/7`
`\implies y = -11/7`
Hence, `barx = -4/7` and `bary = -11/7`
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RELATED QUESTIONS
Read the following statements and choose the correct option:
- If r = 0, then regression lines are not defined.
- If r = 0, then regression lines are parallel.
- If r = 0, then regression lines are perpendicular.
- If r = ±1, then regression lines coincide.
Which of the following is correct?
The random variables have regression lines 3x + 2y − 26 = 0 and 6x + y − 31 = 0. Calculate mean value of x and y.