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Question
The feasible solution for a LPP is shown in Figure. Let Z = 3x – 4y be the objective function. Minimum of Z occurs at ______.
Options
(0, 0)
(0, 8)
(5, 0)
(4, 10)
Solution
The feasible solution for a LPP is shown in Figure. Let Z = 3x – 4y be the objective function. Minimum of Z occurs at (0, 8).
Explanation:
| Corner points | Value of Z = 3x – 4y | |
| O(0, 0) | Z = 0 | |
| A(5, 0) | Z = 3(5) – 0 = 15 | |
| B(6, 5) | Z = 3(6) – 4(5) = – 2 | |
| C(6, 8 | Z = 3(6) – 4(8) = – 14 | |
| D(4, 10) | Z = 3(4) – 4(10) = – 28 | ← Minimum |
| E(0, 8) | Z = 3(0) – 4(8) = – 32 |
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