Advertisements
Advertisements
Question
The figure shows a network of five capacitors connected to a 100 V supply. Calculate the total energy stored in the network.
Solution
As the both 3 uF capacitors are connected in parallel, so net capacitance between branch EH = 3 + 3 = 6μF
Similarly, the capacitance 2 uF and 1uF at corner B are also connected in parallel, so the net capacitance of branch FG = 2 + 1 = 3 μF
If reconstruct the given figure according to the above calculations, we can see that 6 μF capacitors and 3 μF capacitors are connected in series and another 2 μF capacitor is connected in parallel with both of them.
Hence net capacitance Between D and C `= 2 + (3xx6)/(3+6) = 2+2 = 4 mu"F"`
The total capacitance of the circuit, Cnet = 4μF
Total voltage applied, V = 100V
Energy stored in the network `= 1/2 "C"_"net""V"^2 = 1/2 xx 4xx10^-6 xx (100)^2 = 0.02 "J"`
APPEARS IN
RELATED QUESTIONS
Three capacitors each of capacitance 9 pF are connected in series.
- What is the total capacitance of the combination?
- What is the potential difference across each capacitor if the combination is connected to a 120 V supply?
An electrical technician requires a capacitance of 2 µF in a circuit across a potential difference of 1 kV. A large number of 1 µF capacitors are available to him each of which can withstand a potential difference of not more than 400 V. Suggest a possible arrangement that requires the minimum number of capacitors.
A circuit is set up by connecting inductance L = 100 mH, resistor R = 100 Ω and a capacitor of reactance 200 Ω in series. An alternating emf of \[150\sqrt{2}\] V, 500/π Hz is applies across this series combination. Calculate the power dissipated in the resistor.
The plates of a capacitor are 2⋅00 cm apart. An electron-proton pair is released somewhere in the gap between the plates and it is found that the proton reaches the negative plate at the same time as the electron reaches the positive plate. At what distance from the negative plate was the pair released?
An ac circuit consists of a series combination of circuit elements X and Y. The current is ahead of the voltage in phase by `pi /4` . If element X is a pure resistor of 100Ω ,
(a) name the circuit element Y.
(b) calculate the rms value of current, if rms value of voltage is 141V.
(c) what will happen if the ac source is replaced by a dc source ?
An ac circuit consists of a series combination of circuit elements X and Y. The current is ahead of the voltage in phase by `pi/4`. If element X is a pure resistor of 100 Ω,
(a) name the circuit element Y.
(b) calculate the rms value of current, if rms of voltage is 141 V.
(c) what will happen if the ac source is replaced by a dc source
Three capacitors each of 4 µF are to be connected in such a way that the effective capacitance is 6µF. This can be done by connecting them:
The equivalent capacitance of the combination shown in the figure is ______.
The equivalent capacitance of the combination shown in the figure is ______.
The total charge on the system of capacitors C1 = 1 µF, C2 = 2 µF, C3 = 4 µF and C4 = 3 µF connected in parallel is ______. (Assume a battery of 20 V is connected to the combination)
