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Question
The following letters A, D, M, N, O, S, U, Y of the English alphabet are written on separate cards and put in a box. The cards are well shuffled and one card is drawn at random. What is the probability that the card drawn is a letter of the word,
- MONDAY?
- Which does not appear in MONDAY?
- Which appears both in SUNDAY and MONDAY?
Solution
Total outcomes n(s) = 8
a. Favourable outcomes, n(E) = 6
`P(E) = (n(E))/(n(S))`
= `6/8`
= `3/4`
b. `P(barE) = 1 - P(E)`
= `1 - 3/4`
= `(4 - 3)/4`
= `1/4`
c. Favourable outcomes = uncommon letters
= N, D, A, Y
= 4
Then, required probability = `4/8 = 1/2`
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