Advertisements
Advertisements
Question
The G.C.D of x4 – y4 and x2 – y2 is
Options
x4 – y4
x2 – y2
(x + y)2
(x + y)4
Solution
x2 – y2
Explanation;
Hint
x4 – y4 = (x2)2 – (y2)2
= (x2 + y2)(x2 – y2)
x2 – y2 = (x2 – y2)
G.C.D = x2 – y2
APPEARS IN
RELATED QUESTIONS
Find the HCF of the following number.
24, 36
Find the prime factor of the following numbers and find their LCM and HCF.
114, 76
Find the HCF of the numbers in each of the following, using the prime factorization method:
84, 98
Find the HCF of the numbers in each of the following, using the prime factorization method:
504, 980
Find the HCF of the following numbers: 20, 28, and 36.
Find the G.C.D of the following:
2a2 + a, 4a2 – 1
Find the G.C.D of the following:
3a2, 5b3, 7c4
The HCF of 17 and 18 is 1
HCF of co-prime numbers 4 and 15 was found as follows by factorization:
4 = 2 × 2 and 15 = 3 × 5 since there is no common prime factor, so HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF?
Find the HCF of the following numbers:
18, 48
