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Question
The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm3 of wood has a mass of 0.6 gm.
Solution
Given data is as follows:
Inner diameter = 24cm
Outer diameter = 28cm
h = 35cm
Mass of 1 cm3 of wood = 0.6gm
We have to find the mass of the pipe.
In this problem the inner and outer diameter of the pipe is given. Let us first find out the radius.
Inner radius (r) = 12cm
Outer radius (R) = 14cm
Volume of the hollow pipe = `pi (R^2 - r^2 ) h`
`= 22/7 xx ( 14^2 - 12^2 ) xx 35 `
`= 22 xx 5 xx 2 xx 26`
` = 5720 cm ^3`
It is given that,
1 cm3 of wood weighs 0.6gm
Therefore, 5720 cm3 of wood will weigh 5720 × .6 = 3432gm
= 3.432kg
Therefore, weight of the wooden pipe = 3.432kg
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