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Question
The intercepts made on the coordinate axes by the plane 2x + y − 2z = 3 are:
Options
`(-3)/2, -3, (-3)/2`
`3/2, 3, (-3)/2`
`3/2, -3, (-3)/2`
`3/2, 3, 3/2`
Solution
`3/2, 3, (-3)/2`
Explanation:
Given the equation of the plane is
2x + y − 2z = 3
Divide by 3 on both sides
`(2"x")/3 + "y"/3 - (2"z")/3 = 1`
or `"x"/(3/2) + "y"/3 + "z"/((-3)/2) = 1`
Hence, the intercepts made on coordinates axes are `3/2, 3, (-3)/2`.
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