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Question
The marks obtained by 45 students of a class in a test are given below:
Marks | 40-45 | 45-50 | 50-55 | 55-60 | 60-65 | 65-70 |
Number of students | 8 | 9 | 10 | 9 | 5 | 4 |
Find the mean and median marks.
Sum
Solution
We have,
Marks | Number of students (fi) | Mid-point (xi) | xi fi | cf |
40-45 | 8 | 42.5 | 340 | 8 |
45-50 | 9 | 47.5 | 427.5 | 17 |
50-55 | 10 | 52.5 | 525 | 27 |
55-60 | 9 | 57.5 | 517.5 | 36 |
60-65 | 5 | 62.5 | 312.5 | 41 |
65-70 | 4 | 67.5 | 270 | 45 |
`sum fi = 45` | `sum fi x i = 2392.5` |
Mean = `(sum fi xx xi)/(sum fi)`
= `2392.5/45`
= 53167
Since, N = 45 ⇒ `N/2 = 45/2` = 22.5
Which lies in the class interval 50-55.
Here, l = 50, h = 5, f = 10, cf = 17
Median = `l + [( N/2 - cf)/f] xx h`
= `50 + [(225 - 17)/10] xx 5`
= 52.75
Therefore, mean is 53.167 and median marks is 52.75.
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