Advertisements
Advertisements
Question
The mean of 18, 28, x, 32, 14 and 36 is 23. Find the value of x. Sum of data
Solution
∵ Mean = `"Sum of data"/"Number of data"`
`=> 23 = (18 + 28 + x + 32 + 14 + 36)/6`
`=> 23 = (128 + x)/6`
`=> 23 xx 6 = 128 + x`
⇒ 138 = 128 + x
⇒ 138 - 128 = x
∴ x = 10
APPEARS IN
RELATED QUESTIONS
From the following cumulative frequency table, draw ogive and then use it to find:
- Median
- Lower quartile
- Upper quartile
Marks (less than) | 10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 | 90 | 100 |
Cumulative frequency | 5 | 24 | 37 | 40 | 42 | 48 | 70 | 77 | 79 | 80 |
The marks of 200 students in a test were recorded as follows:
Marks | No. of students |
10-19 | 7 |
20-29 | 11 |
30-39 | 20 |
40-49 | 46 |
50-59 | 57 |
60-69 | 37 |
70-79 | 15 |
80-89 | 7 |
Construct the cumulative frequency table. Drew the ogive and use it too find:
(1) the median and
(2) the number of student who score more than 35% marks.
Find the mean (correct to one place of decimal) by using short-cut method.
x |
40 |
41 |
43 |
45 |
46 |
49 |
50 |
f |
14 |
28 |
38 |
50 |
40 |
20 |
10 |
The percentage marks obtained in 10 subjects by a student are 84, 88, 72, 91, 68, 75, 98, 96, 79 and 86. Find the median of the marks obtained.
The marks of 200 students in a test is given below :
Marks% | 10-19 | 20-29 | 30-39 | 40-49 | 50-59 | 60-69 | 70-79 | 80-89 |
No. of Students | 7 | 11 | 20 | 46 | 57 | 37 | 15 | 7 |
Draw an ogive and find the number of students who scored more than 35% marks
Find the median of:
63, 17, 50, 9, 25, 43, 21, 50, 14 and 34
Find the mean of all factors of 10.
If the mean of 8, 10, 7, x + 2 and 6 is 9, find the value of x.
Find the median of 3.2, 4.8, 5.6, 5.6, 7.3, 8.9 and 9.1
Find the median of the given values : 47, 53, 62, 71, 83, 21, 43, 47, 41