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Question
The normal boiling point of water is 100°C or 212°F and the freezing point of water is 0°C or 32°F. Find the value of C for 98.6°F
Solution
For 98.6°F To find C.
(1) ⇒ C = `5/9 (98.6^circ - 32^circ)`
C = `5/9 xx 66.6^circ`
C = `333/9` = 37°
C = 37°
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