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The overall width in cm of several wide-screen televisions are 97.28 cm, 9849 cm 98125 cm and 97.94 cm. Express these numbers as rational numbers in the form pq and arrange the widths in ascending - Mathematics

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Question

The overall width in cm of several wide-screen televisions are 97.28 cm, `98 4/9` cm `98 1/25` cm and 97.94 cm. Express these numbers as rational numbers in the form `p/q` and arrange the widths in ascending order.

Sum

Solution

From the question,

The overall width in cm of several wide screen television are,

97.28 cm = `9728/100`  ...[∵ By the decimal removing method]

By dividing both numerator and denominator by 4 we get,

= `2432/25` cm

By converting mixed fraction into improper fraction we get,

`98 4/9` cm = `886/9` cm

By converting mixed fraction into improper fraction we get,

`98 1/25` cm = `2451/25` cm

97.94 cm = `9794/100`   ...[∵ By the decimal removing method]

By dividing both numerator and denominator by 2 we get,

= `4897/50` cm

Now, we have to take the LCM of denominators to arrange them In ascending order.

The LCM of the denominators 25, 9, 25 and 50 is 450

∴ `2432/25 = [(2432 xx 18)/(25 xx 18)]`

= `43776/450`

`886/9 = [(886 xx 50)/(9 xx 50)]`

= `44300/450`

`2451/25 = [(2451 xx 18)/(25 xx 18)]`

= `44118/450`

`4897/50 = [(4897 xx 9)/(50 xx 9)]`

= `44073/450`

Then,

Now, 43776 < 44073 < 44118 < 44300

Hence, in ascending order = `2432/25 < 4897/50 < 2451/25 < 886/9`

∴ `97.28 < 97.94 < 98 1/25 "cm" < 98 4/9 "cm"`.

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Chapter 1: Rational Numbers - Exercise [Page 26]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 1 Rational Numbers
Exercise | Q 147. | Page 26

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