Advertisements
Advertisements
Question
The photograph of a house occupies an area of 1.75 cm2on a 35 mm slide. The slide is projected on to a screen, and the area of the house on the screen is 1.55 m2. What is the linear magnification of the projector-screen arrangement?
Solution
Area of the house on the slide = 1.75 cm2
Area of the image of the house formed on the screen = 1.55 × 104 cm2
Arial magnification, ma =` "Area of image"/"Area of object" = (1.55 xx 10^4)/1.75 `
= 8857.14
∴ Linear magnifications, `m_l = sqrtm_a`
=`sqrt(8857.14)` = 94.11
APPEARS IN
RELATED QUESTIONS
How many significant figures are present in the 500.0?
A student measures the thickness of a human hair by looking at it through a microscope of magnification 100. He makes 20 observations and finds that the average width of the hair in the field of view of the microscope is 3.5 mm. What is the estimate on the thickness of hair?
State the number of significant figures in the following:
6.320 J
Just as precise measurements are necessary in science, it is equally important to be able to make rough estimates of quantities using rudimentary ideas and common observations. Think of ways by which you can estimate the following (where an estimate is difficult to obtain, try to get an upper bound on the quantity):-
the wind speed during a storm
Answer the following question.
Describe what is meant by order of magnitude.
The radius of the circle is 3.12 m. Calculate the area of the circle with regard to significant figures.
How many significant figures should be present in the answer of the following calculations?
`(2.5 xx 1.25 xx 3.5)/2.01`
Assertion (A): Significant figures for 0.200 is 3 where as for 200 it is 1.
Reason (R): Zero at the end or right of a number are significant provided they are not on the right side of the decimal point.
Why do we have different units for the same physical quantity?
Using the rules for significant figures, the correct answer for the expression `(0.02858 xx 0.112)/(0.5702)` will be ______.
