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Question
The polynomials ax3 + 3x2 − 3 and 2x3 − 5x + a when divided by (x − 4) leave the remainders R1 and R2 respectively. Find the values of the following case, if R1 + R2 = 0.
Solution
Let us denote the given polynomials as
`f(x) = ax^3 + 3x^2 -3`
`g(x) = 2x^3 - 5x + a,`
` h(x) = x-4`
Now, we will find the remainders R1and R2 when f(x) and g(x)respectively are divided by h(x).
By the remainder theorem, when f(x)is divided by h(x) the remainder is
`R_1 = f(4)`
` = a(4)^3 + 3(4)^2 -3`
` = 64a + 48 - 3`
` = 64a + 48`
By the remainder theorem, when g(x) is divided by h(x) the remainder is
`R_2 = g(4)`
`2(4)^3 - 5(4) + a`
`128 - 20`
` a+108`
By the given condition,
R1 + R2 = 0
`⇒ 64 + 45 + 108 = 0 `
`⇒ 65a + 153 = 0 `
`⇒ 65a = -153 `
`⇒ a= -153/65 `
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