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The Radius of the Base and the Height of a Solid Right Circular Cylinder Are in the Ratio 2 : 3 and Its Volume is 1617 Cm3. Find the Total Surface Area of the Cylinder. - Mathematics

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Question

The radius of the base and the height of a solid right circular cylinder are in the ratio 2 : 3 and its volume is 1617 cm3. Find the total surface area of the cylinder.

Sum

Solution

Let the radius of the cylinder be 2x cm and its height be 3x cm. 

Then,Volume of the cylinder`=pi"r"^2"h"`

`=22/7xx(2x)^2xx3x`

Therefore, 

`22/7xx(2x)^2xx3x=1617`

`=>22/7xx4x^2xx3x=1617`

`=> 22/7xx12x^3 = 1617`

`=>x^3=(1617+7/22xx12)`

`=> x^3=(7/2xx7/2xx7/2)`

`=> x^3 = (7/2)^3`

`=> x = 7/2`

Now, r = 7 cm and `"h" = 21/2  "cm"`

Hence,the total surface area of the cylinder:

(2πrh + 2πr2)

= 2πr(h + r)

`= 2xx22/7xx7xx(21/2+7)"cm"^`

`= (2xx(22)/7xx7xx(35)/2) "cm"^2 `

= 770 cm

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Chapter 19: Volume and Surface Area of Solids - Formative Assessment [Page 937]

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RS Aggarwal Mathematics [English] Class 10
Chapter 19 Volume and Surface Area of Solids
Formative Assessment | Q 11 | Page 937

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