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Question
The radius of a circle is 8 cm and the length of one of its chords is 12 cm. Find the distance of the chord from the centre.
Solution
Radius of circle (OA) = 8 cm ......(Given)
Chord (AB) = 12cm .......(Given)
Draw a perpendicular OC on AB.
We know, perpendicular from centre to chord bisects the chord
Which implies, AC = BC = `12/2` = 6 cm
In right ΔOCA:
Using Pythagoras theorem,
OA2 = AC2 + OC2
64 = 36 + OC2
OC2 = 64 – 36 = 28
or OC = √28 = 5.291 (approx.)
The distance of the chord from the centre is 5.291 cm.
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