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Question
Find the length of a chord which is at a distance of 5 cm from the centre of a circle ofradius 10 cm.
Solution
Given that
Distance (OC)=5cm
Radius of circle (OA)10cm
In OCA by Pythagoras theorem
`AC^2+OC^2=OA^2`
`⇒AC^2+5^2=10^2`
`⇒AC=sqrt75=8.66cm`
WRK, the perpendicular from center to chord bisects the chord
`∴AC=BC=8.66cm`
Then chord AB=8.66+8.66
= 17.32 cm
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