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Question
Find the length of a chord which is at a distance of 4 cm from the centre of the circle of radius 6 cm.
Solution
Radius of circle (OA)= 6cm
Distant (OC)=4cm
In Δ OCA by Pythagoras theorem
`AC^2+OC^2=OA^2`
⇒`AC^2+4^2=6^2`
⇒`AC^2=36-16`
⇒`AC=sqrt20 =4.47 cm`
WKT, the perpendicular distance from center to chord bisects the chord.
`AC=BC=4.47cm `
`Then , AB = 4.47+4.47`
`8.94 cm `
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