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Question
The roots of the equation `2x^2-6x+3=0` are
(a) real, unequal and rational (b) real, unequal and irrational (c) real and equal (d) imaginary
Solution
(b) real, unequal and irrational
∵`D=(b^2-4ac)`
=`(-6)^2-4xx2xx3`
=`36-24`
=`12`
12 is greater than 0 and it is not a perfect square; therefore, the roots of the equation are real, unequal and irrational.
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