Advertisements
Advertisements
Question
If the quadratic equation `px^2-2sqrt5px+15=0` has two equal roots then find the value of p.
Solution
It is given that the quadratic equation `px^2-2sqrt5px+15=0` has two equal roots.
∴`D=0`
⇒`(-2sqrt5p)^2-4xxpxx15=0`
⇒`20p^2-60p=0`
⇒` 20p(p-3)=0`
⇒`p=0 or p-3=0`
⇒`p=0 or p=3`
For `p=0`, we get `15=0` which is not true.
∴`p≠0`
Hence, the value of p is 3.
APPEARS IN
RELATED QUESTIONS
If the product of the roots of the equation `x^2-3x+k=10` is-2 then the value of k is
(a) -2 (b) -8 (c) 8 (d) 12
The roots of a quadratic equation are 5 and -2. Then, the equation is
(a)`x^2-3x+10=0` (b)`x^2-3x-10=0` (c)x^2+3x-10=0 (d)`x^2+3x+10=0`
The roots of `ax^2+bx+c=0`,a≠0 are real and unequal, if `(b^2-4ac)` is
(a)>0 (b)=0 (c)<0 (d)none of these
Find the solution of the quadratic equation `3sqrt3x^2+10x+sqrt3=0`
If 1 is a root of the equation `ay^2+ay+3=0` and `y^2+y+b=0` then find the value of ab.
Decide whether the following equation is quadratic equation or not.
(m + 2) (m – 5) = 0
Write the following equation in the form ax2 + bx + c= 0, then write the values of a, b, c for the equation.
3m2 = 2m2 – 9
Which one is the quadratic equation?
Solve any four of the following.
Find the value of y in the equation x + y = 12, when x = 5
Let p and q be two positive numbers such that p + q = 2 and p4 + q4 = 272. Then p and q are roots of the equation ______.
