Advertisements
Advertisements
Question
The table top is in the shape of a trapezium with measurements given in the figure. Find the cost of the glass used to cover the table at the rate of ₹ 6 per 10 sq.cm
Solution
Length of the parallel sides a = 200 cm
b = 150 cm
Height h = 50 cm
Area of the trapezium = `1/2` × h (a + b) sq.units
= `1/2` × 50(200+ 150) cm2
= `1/2` × 50 × 350 cm2
= 8750 cm2
Cost for 10 sq.cm glass = ₹ 68
∴ Cost of 8750 cm2 glass = `8750/10 xx 6` = ₹ 5250
Cost of glass used = ₹ 5,250
APPEARS IN
RELATED QUESTIONS
Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm.
The area of a trapezium is 960 cm2. If the parallel sides are 34 cm and 46 cm, find the distance between them.
Find the area of a trapezium whose parallel sides are 25 cm, 13 cm and the other sides are 15 cm each.
Find the area of the pentagon shown in fig. 20.48, if AD = 10 cm, AG = 8 cm, AH = 6 cm, AF = 5 cm, BF = 5 cm, CG = 7 cm and EH = 3 cm.
The parallel sides of a trapezium are in ratio 3: 4. If the distance between the parallel sides is 9 dm and its area is 126 dm2; find the lengths of its parallel sides.
Find the missing values.
Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
13 cm | 28 cm | 492 sq.cm |
Find the area of a trapezium whose parallel sides are 24 cm and 20 cm and the distance between them is 15 cm
In a trapezium if the sum of the parallel sides is 10 cm and the area is 140 sq.cm, then the height is
The area of a trapezium become 4 times if its height gets doubled.
The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.