English
Karnataka Board PUCPUC Science Class 11

The Temperature of the Atmosphere at a High Altitude is Around 500°C. Yet an Animal There Would Freeze to Death and Not Boil. Explain. - Physics

Advertisements
Advertisements

Question

The temperature of the atmosphere at a high altitude is around 500°C. Yet an animal there would freeze to death and not boil. Explain.

Short Note

Solution

The temperature of the atmosphere at a high altitude is around 500°C, but density of air molecule is extremely low at this height. So, very less molecules of air collide with the body of the animal and transfer very less amount of heat. That is why the animal present there would freeze to death instead boiling.

shaalaa.com
Newton’s Law of Cooling
  Is there an error in this question or solution?
Chapter 6: Heat Transfer - Short Answers [Page 97]

APPEARS IN

HC Verma Concepts of Physics Vol. 2 [English] Class 11 and 12
Chapter 6 Heat Transfer
Short Answers | Q 8 | Page 97

RELATED QUESTIONS

A body cools from 80 °C to 50 °C in 5 minutes. Calculate the time it takes to cool from 60 °C to 30 °C. The temperature of the surroundings is 20 °C.


On a hot summer day we want to cool our room by opening the refrigerator door and closing all the windows and doors. Will the process work?


An ordinary electric fan does not cool the air, still it gives comfort in summer. Explain


Newton's law of cooling is a special case of


Answer the following question.

State Newton’s law of cooling and explain how it can be experimentally verified.


Solve the following problem.

A metal sphere cools at the rate of 0.05 ºC/s when its temperature is 70 ºC and at the rate of 0.025 ºC/s when its temperature is 50 ºC. Determine the temperature of the surroundings and find the rate of cooling when the temperature of the metal sphere is 40 ºC.


A metal sphere cools from 80 °C to 60 °C in 6 min. How much time with it take to cool from 60 °C to 40 °C if the room temperature is 30 °C?


A bucket full of hot water cools from 85 °C to 80 °C in time T1, from 80 °C to 75 °C in time T2 and from 75 °C to 70 °C in time T3, then ______.


A metal sphere cools from 66° C to 57° C in 10 minutes and to 44° C in the next 10 minutes. The ratio of fall of temperature of first 10 minutes to next ten minutes is ____________.


A tub of hot water cools from 80°C to 75°C in time t1 from 75°C to 70°C in time t2, and from 70°C to 65°C in time t3 then:


Two circular discs A and B with equal radii are blackened. They are heated to the same temperature and are cooled under identical conditions. What inference do you draw from their cooling curves?


A glass full of hot milk is poured on the table. It begins to cool gradually. Which of the following is correct?

  1. The rate of cooling is constant till milk attains the temperature of the surrounding.
  2. The temperature of milk falls off exponentially with time.
  3. While cooling, there is a flow of heat from milk to the surrounding as well as from surrounding to the milk but the net flow of heat is from milk to the surounding and that is why it cools.
  4. All three phenomenon, conduction, convection and radiation are responsible for the loss of heat from milk to the surroundings.

Is the bulb of a thermometer made of diathermic or adiabatic wall?


One day in the morning, Ramesh filled up 1/3 bucket of hot water from geyser, to take bath. Remaining 2/3 was to be filled by cold water (at room temperature) to bring mixture to a comfortable temperature. Suddenly Ramesh had to attend to something which would take some times, say 5-10 minutes before he could take bath. Now he had two options: (i) fill the remaining bucket completely by cold water and then attend to the work, (ii) first attend to the work and fill the remaining bucket just before taking bath. Which option do you think would have kept water warmer? Explain.


According to Newton's law of cooling, the rate of cooling of the body is proportional to (Δθ), where Δθ is the difference between the temperature of the body and the surroundings, and n is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×