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Question
Solution
Let final temp. of mixture = T°C
∴ Rise in temp. of cold water = T - t = 15°C
Let C be the Specific heat capacity of water
Heat lost by hot water = Heat gained by cold water
Mass × C × fall in temperature = Mass × C × Rise in temperature
⇒ 300 × C × (50 - T) = 600 × C × (T - t)
⇒ 50 - T = 2 × [15]
⇒ T = 50 - 30 = 20
But rise in temperature = T - initial temperature of cold water
⇒ 15 = 20 - t
∴ t = 20 - 15 = 5°C
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