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Question
(a) Calculate the heat capacity of a copper vessel of mass 150g if the specific heat capacity of copper is `410 J kg^-1 K^-1`
(b) How much heat energy will be required to increase the temperature of the vessel in part (a) from 25°C to 35°C?
Solution
Mass of copper vessel = 150 g
= 0.15 kg
The specific heat capacity of copper = `410 J kg^-1K^-1`.
Heat capacity = Mass × specific heat capacity
= `0.15 kg × 410Jkg^-1K^-1`
= `61.5JK^-1`
Change in temperature= (35 − 25)°C = 10°C = 10K
(ii) Energy required to increase the temperature of vessel
ΔQ = mcΔT
= 0.15 × 410 × 10
= 615 J
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